Base | Representation |
---|---|
bin | 11101000111101100000… |
… | …111101001011000011010 |
3 | 21002022020120121201211021 |
4 | 131013230013221120122 |
5 | 230241244013020442 |
6 | 4131145152353054 |
7 | 264401435501263 |
oct | 35075407513032 |
9 | 7068216551737 |
10 | 2001121220122 |
11 | 70174183a092 |
12 | 2839b754578a |
13 | 11692193492b |
14 | 6cbd775396a |
15 | 370c1655e67 |
hex | 1d1ec1e961a |
2001121220122 has 4 divisors (see below), whose sum is σ = 3001681830186. Its totient is φ = 1000560610060.
The previous prime is 2001121220093. The next prime is 2001121220173. The reversal of 2001121220122 is 2210221211002.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1921935822921 + 79185397201 = 1386339^2 + 281399^2 .
It is a super-2 number, since 2×20011212201222 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2001121220096 and 2001121220105.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500280305029 + ... + 500280305032.
Almost surely, 22001121220122 is an apocalyptic number.
2001121220122 is a deficient number, since it is larger than the sum of its proper divisors (1000560610064).
2001121220122 is a wasteful number, since it uses less digits than its factorization.
2001121220122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1000560610063.
The product of its (nonzero) digits is 64, while the sum is 16.
Adding to 2001121220122 its reverse (2210221211002), we get a palindrome (4211342431124).
The spelling of 2001121220122 in words is "two trillion, one billion, one hundred twenty-one million, two hundred twenty thousand, one hundred twenty-two".
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