Base | Representation |
---|---|
bin | 10010101000110000… |
… | …101110100010000111 |
3 | 1220122121122001022111 |
4 | 102220300232202013 |
5 | 311440332334413 |
6 | 13105405441451 |
7 | 1305616343434 |
oct | 225060564207 |
9 | 56577561274 |
10 | 20011214983 |
11 | 853989a001 |
12 | 3a65870287 |
13 | 1b6bb03516 |
14 | d7b9a4b8b |
15 | 7c1c33d3d |
hex | 4a8c2e887 |
20011214983 has 2 divisors, whose sum is σ = 20011214984. Its totient is φ = 20011214982.
The previous prime is 20011214911. The next prime is 20011215011. The reversal of 20011214983 is 38941211002.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20011214983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20011214383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10005607491 + 10005607492.
It is an arithmetic number, because the mean of its divisors is an integer number (10005607492).
Almost surely, 220011214983 is an apocalyptic number.
20011214983 is a deficient number, since it is larger than the sum of its proper divisors (1).
20011214983 is an equidigital number, since it uses as much as digits as its factorization.
20011214983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 31.
Adding to 20011214983 its reverse (38941211002), we get a palindrome (58952425985).
The spelling of 20011214983 in words is "twenty billion, eleven million, two hundred fourteen thousand, nine hundred eighty-three".
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