Base | Representation |
---|---|
bin | 101101100000000001000000… |
… | …101010011001001000000111 |
3 | 222020112112120100211000020221 |
4 | 231200001000222121020013 |
5 | 202212114241441010043 |
6 | 1545334135344405211 |
7 | 60102425615106406 |
oct | 5540010052311007 |
9 | 866475510730227 |
10 | 200112201110023 |
11 | 58842120680a54 |
12 | 1a53b103316807 |
13 | 87876657b8747 |
14 | 375b6a729363d |
15 | 182059e5228ed |
hex | b60040a99207 |
200112201110023 has 2 divisors, whose sum is σ = 200112201110024. Its totient is φ = 200112201110022.
The previous prime is 200112201110009. The next prime is 200112201110047. The reversal of 200112201110023 is 320011102211002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200112201110023 - 221 = 200112199012871 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 200112201109979 and 200112201110006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200112201110323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100056100555011 + 100056100555012.
It is an arithmetic number, because the mean of its divisors is an integer number (100056100555012).
Almost surely, 2200112201110023 is an apocalyptic number.
200112201110023 is a deficient number, since it is larger than the sum of its proper divisors (1).
200112201110023 is an equidigital number, since it uses as much as digits as its factorization.
200112201110023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 200112201110023 its reverse (320011102211002), we get a palindrome (520123303321025).
The spelling of 200112201110023 in words is "two hundred trillion, one hundred twelve billion, two hundred one million, one hundred ten thousand, twenty-three".
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