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20011319953 is a prime number
BaseRepresentation
bin10010101000110001…
…001000001010010001
31220122121211101022021
4102220301020022101
5311440344214303
613105412011441
71305620261452
oct225061101221
956577741267
1020011319953
118539960959
123a65900b81
131b6bb3c231
14d7b9d1129
157c1c54ebd
hex4a8c48291

20011319953 has 2 divisors, whose sum is σ = 20011319954. Its totient is φ = 20011319952.

The previous prime is 20011319929. The next prime is 20011319959. The reversal of 20011319953 is 35991311002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19519722369 + 491597584 = 139713^2 + 22172^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20011319953 is a prime.

It is a super-2 number, since 2×200113199532 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (20011319959) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10005659976 + 10005659977.

It is an arithmetic number, because the mean of its divisors is an integer number (10005659977).

Almost surely, 220011319953 is an apocalyptic number.

It is an amenable number.

20011319953 is a deficient number, since it is larger than the sum of its proper divisors (1).

20011319953 is an equidigital number, since it uses as much as digits as its factorization.

20011319953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7290, while the sum is 34.

The spelling of 20011319953 in words is "twenty billion, eleven million, three hundred nineteen thousand, nine hundred fifty-three".