Base | Representation |
---|---|
bin | 11101000111101100110… |
… | …011001110110001101111 |
3 | 21002022021101010012110221 |
4 | 131013230303032301233 |
5 | 230241304424123422 |
6 | 4131150241312211 |
7 | 264401634555343 |
oct | 35075463166157 |
9 | 7068241105427 |
10 | 2001132645487 |
11 | 701748233138 |
12 | 2839bb335667 |
13 | 1169241051c1 |
14 | 6cbd9089623 |
15 | 370c26613c7 |
hex | 1d1ecccec6f |
2001132645487 has 2 divisors, whose sum is σ = 2001132645488. Its totient is φ = 2001132645486.
The previous prime is 2001132645469. The next prime is 2001132645517. The reversal of 2001132645487 is 7845462311002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2001132645487 - 27 = 2001132645359 is a prime.
It is a super-3 number, since 3×20011326454873 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2001132645467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000566322743 + 1000566322744.
It is an arithmetic number, because the mean of its divisors is an integer number (1000566322744).
Almost surely, 22001132645487 is an apocalyptic number.
2001132645487 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001132645487 is an equidigital number, since it uses as much as digits as its factorization.
2001132645487 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 322560, while the sum is 43.
Adding to 2001132645487 its reverse (7845462311002), we get a palindrome (9846594956489).
The spelling of 2001132645487 in words is "two trillion, one billion, one hundred thirty-two million, six hundred forty-five thousand, four hundred eighty-seven".
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