200113465440 has 384 divisors, whose sum is σ = 770359984128. Its totient is φ = 42622156800.

The previous prime is 200113465427. The next prime is 200113465451. The reversal of 200113465440 is 44564311002.

It is a super-3 number, since 3×200113465440³ (a number of 35 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 200113465398 and 200113465407.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 5751777 + ... + 5786463.

It is an arithmetic number, because the mean of its divisors is an integer number (2006145792).

Almost surely, 2^200113465440 is an apocalyptic number.

200113465440 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 200113465440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (385179992064).

200113465440 is an abundant number, since it is smaller than the sum of its proper divisors (570246518688).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

200113465440 is a wasteful number, since it uses less digits than its factorization.

200113465440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34830 (or 34822 counting only the distinct ones).

The product of its (nonzero) digits is 11520, while the sum is 30.

Adding to 200113465440 its reverse (44564311002), we get a palindrome (244677776442).

The spelling of 200113465440 in words is "two hundred billion, one hundred thirteen million, four hundred sixty-five thousand, four hundred forty".