200114113 has 2 divisors, whose sum is σ = 200114114. Its totient is φ = 200114112.

The previous prime is 200114087. The next prime is 200114129. The reversal of 200114113 is 311411002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 199713424 + 400689 = 14132^2 + 633^2 .

It is a cyclic number.

It is not a de Polignac number, because 200114113 - 2²¹ = 198016961 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 200114093 and 200114102.

It is not a weakly prime, because it can be changed into another prime (200111113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100057056 + 100057057.

It is an arithmetic number, because the mean of its divisors is an integer number (100057057).

Almost surely, 2^200114113 is an apocalyptic number.

It is an amenable number.

200114113 is a deficient number, since it is larger than the sum of its proper divisors (1).

200114113 is an equidigital number, since it uses as much as digits as its factorization.

200114113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 200114113 is about 14146.1695522145. The cubic root of 200114113 is about 584.9147493080.

Adding to 200114113 its reverse (311411002), we get a palindrome (511525115).

The spelling of 200114113 in words is "two hundred million, one hundred fourteen thousand, one hundred thirteen".