Search a number
-
+
200120121000113 = 9719311068407059
BaseRepresentation
bin101101100000001000011000…
…101110011000000010110001
3222020120022000022111010000112
4231200020120232120002301
5202212232001434000423
61545341525303231105
760103126104055106
oct5540103056300261
9866508008433015
10200120121000113
1158845515202666
121a540753748495
138788328560442
14375bc19066aad
1518208b4996a78
hexb60218b980b1

200120121000113 has 8 divisors (see below), whose sum is σ = 202287919112160. Its totient is φ = 197954459706240.

The previous prime is 200120121000089. The next prime is 200120121000301. The reversal of 200120121000113 is 311000121021002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 200120121000113 - 214 = 200120120983729 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200120121000013) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 534016223 + ... + 534390836.

It is an arithmetic number, because the mean of its divisors is an integer number (25285989889020).

Almost surely, 2200120121000113 is an apocalyptic number.

It is an amenable number.

200120121000113 is a deficient number, since it is larger than the sum of its proper divisors (2167798112047).

200120121000113 is a wasteful number, since it uses less digits than its factorization.

200120121000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1068409087.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 200120121000113 its reverse (311000121021002), we get a palindrome (511120242021115).

The spelling of 200120121000113 in words is "two hundred trillion, one hundred twenty billion, one hundred twenty-one million, one hundred thirteen", and thus it is an aban number.

Divisors: 1 97 1931 187307 1068407059 103635484723 2063094030929 200120121000113