Base | Representation |
---|---|
bin | 101101100000001000011000… |
… | …101110011000000010110000 |
3 | 222020120022000022111010000111 |
4 | 231200020120232120002300 |
5 | 202212232001434000422 |
6 | 1545341525303231104 |
7 | 60103126104055105 |
oct | 5540103056300260 |
9 | 866508008433014 |
10 | 200120121000112 |
11 | 58845515202665 |
12 | 1a540753748494 |
13 | 8788328560441 |
14 | 375bc19066aac |
15 | 18208b4996a77 |
hex | b60218b980b0 |
200120121000112 has 40 divisors (see below), whose sum is σ = 419275447528896. Its totient is φ = 92170468740096.
The previous prime is 200120121000089. The next prime is 200120121000301. The reversal of 200120121000112 is 211000121021002.
It is a junction number, because it is equal to n+sod(n) for n = 200120121000092 and 200120121000101.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7826963163 + ... + 7826988730.
Almost surely, 2200120121000112 is an apocalyptic number.
It is an amenable number.
200120121000112 is an abundant number, since it is smaller than the sum of its proper divisors (219155326528784).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
200120121000112 is a wasteful number, since it uses less digits than its factorization.
200120121000112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15653951965 (or 15653951959 counting only the distinct ones).
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 200120121000112 its reverse (211000121021002), we get a palindrome (411120242021114).
The spelling of 200120121000112 in words is "two hundred trillion, one hundred twenty billion, one hundred twenty-one million, one hundred twelve", and thus it is an aban number.
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