Base | Representation |
---|---|
bin | 1011101001100000100… |
… | …1100010100000111101 |
3 | 201010112210012212220011 |
4 | 2322120021202200331 |
5 | 11234322002224432 |
6 | 231533454223221 |
7 | 20313121364533 |
oct | 2723011424075 |
9 | 633483185804 |
10 | 200121133117 |
11 | 77964187314 |
12 | 329501b4b11 |
13 | 15b43451a89 |
14 | 9986214153 |
15 | 5313e00847 |
hex | 2e9826283d |
200121133117 has 2 divisors, whose sum is σ = 200121133118. Its totient is φ = 200121133116.
The previous prime is 200121133019. The next prime is 200121133133. The reversal of 200121133117 is 711331121002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 149412398521 + 50708734596 = 386539^2 + 225186^2 .
It is a cyclic number.
It is not a de Polignac number, because 200121133117 - 219 = 200120608829 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200121133417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100060566558 + 100060566559.
It is an arithmetic number, because the mean of its divisors is an integer number (100060566559).
Almost surely, 2200121133117 is an apocalyptic number.
It is an amenable number.
200121133117 is a deficient number, since it is larger than the sum of its proper divisors (1).
200121133117 is an equidigital number, since it uses as much as digits as its factorization.
200121133117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 252, while the sum is 22.
Adding to 200121133117 its reverse (711331121002), we get a palindrome (911452254119).
The spelling of 200121133117 in words is "two hundred billion, one hundred twenty-one million, one hundred thirty-three thousand, one hundred seventeen".
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