Base | Representation |
---|---|
bin | 101101100000001001011010… |
… | …001111100010010100101101 |
3 | 222020120101211220211212021101 |
4 | 231200021122033202110231 |
5 | 202212241224333241023 |
6 | 1545342230331203101 |
7 | 60103165252156402 |
oct | 5540113217422455 |
9 | 866511756755241 |
10 | 200121220212013 |
11 | 58845a29729851 |
12 | 1a5409bb8a6491 |
13 | 87884721c6499 |
14 | 375bcc103c2a9 |
15 | 182092b2241ad |
hex | b6025a3e252d |
200121220212013 has 2 divisors, whose sum is σ = 200121220212014. Its totient is φ = 200121220212012.
The previous prime is 200121220211993. The next prime is 200121220212029. The reversal of 200121220212013 is 310212022121002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 198120347723529 + 2000872488484 = 14075523^2 + 1414522^2 .
It is a cyclic number.
It is not a de Polignac number, because 200121220212013 - 25 = 200121220211981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200121220212073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100060610106006 + 100060610106007.
It is an arithmetic number, because the mean of its divisors is an integer number (100060610106007).
Almost surely, 2200121220212013 is an apocalyptic number.
It is an amenable number.
200121220212013 is a deficient number, since it is larger than the sum of its proper divisors (1).
200121220212013 is an equidigital number, since it uses as much as digits as its factorization.
200121220212013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 200121220212013 its reverse (310212022121002), we get a palindrome (510333242333015).
The spelling of 200121220212013 in words is "two hundred trillion, one hundred twenty-one billion, two hundred twenty million, two hundred twelve thousand, thirteen".
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