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20012201141 = 47834184027
BaseRepresentation
bin10010101000110100…
…011111010010110101
31220122200111011001212
4102220310133102311
5311441110414031
613105442531205
71305630621512
oct225064372265
956580434055
1020012201141
11853a402a09
123a66066b05
131b6c08a34a
14d7bb80309
157c1d7b12b
hex4a8d1f4b5

20012201141 has 4 divisors (see below), whose sum is σ = 20016389952. Its totient is φ = 20008012332.

The previous prime is 20012201113. The next prime is 20012201189. The reversal of 20012201141 is 14110221002.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20012201141 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20012206141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2087231 + ... + 2096796.

It is an arithmetic number, because the mean of its divisors is an integer number (5004097488).

Almost surely, 220012201141 is an apocalyptic number.

It is an amenable number.

20012201141 is a deficient number, since it is larger than the sum of its proper divisors (4188811).

20012201141 is an equidigital number, since it uses as much as digits as its factorization.

20012201141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4188810.

The product of its (nonzero) digits is 32, while the sum is 14.

Adding to 20012201141 its reverse (14110221002), we get a palindrome (34122422143).

The spelling of 20012201141 in words is "twenty billion, twelve million, two hundred one thousand, one hundred forty-one".

Divisors: 1 4783 4184027 20012201141