2001221000113 has 2 divisors, whose sum is σ = 2001221000114. Its totient is φ = 2001221000112.

The previous prime is 2001221000063. The next prime is 2001221000131. The reversal of 2001221000113 is 3110001221002.

Together with next prime (2001221000131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1336722131889 + 664498868224 = 1156167^2 + 815168^2 .

It is a cyclic number.

It is not a de Polignac number, because 2001221000113 - 2¹⁷ = 2001220869041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2001221000093 and 2001221000102.

It is not a weakly prime, because it can be changed into another prime (2001221000173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000610500056 + 1000610500057.

It is an arithmetic number, because the mean of its divisors is an integer number (1000610500057).

Almost surely, 2^{2001221000113} is an apocalyptic number.

It is an amenable number.

2001221000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2001221000113 is an equidigital number, since it uses as much as digits as its factorization.

2001221000113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 2001221000113 its reverse (3110001221002), we get a palindrome (5111222221115).

The spelling of 2001221000113 in words is "two trillion, one billion, two hundred twenty-one million, one hundred thirteen", and thus it is an aban number.