Base | Representation |
---|---|
bin | 11101000111110010000… |
… | …101000101000000011111 |
3 | 21002022111112202202100101 |
4 | 131013302011011000133 |
5 | 230242000112211033 |
6 | 4131203123441531 |
7 | 264404061422341 |
oct | 35076205050037 |
9 | 7068445682311 |
10 | 2001221210143 |
11 | 701793224071 |
12 | 283a24b262a7 |
13 | 116939573a1c |
14 | 6cc06b41291 |
15 | 370ca30797d |
hex | 1d1f214501f |
2001221210143 has 2 divisors, whose sum is σ = 2001221210144. Its totient is φ = 2001221210142.
The previous prime is 2001221210089. The next prime is 2001221210161. The reversal of 2001221210143 is 3410121221002.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2001221210143 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2001221210143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2001221510143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000610605071 + 1000610605072.
It is an arithmetic number, because the mean of its divisors is an integer number (1000610605072).
Almost surely, 22001221210143 is an apocalyptic number.
2001221210143 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001221210143 is an equidigital number, since it uses as much as digits as its factorization.
2001221210143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 2001221210143 its reverse (3410121221002), we get a palindrome (5411342431145).
The spelling of 2001221210143 in words is "two trillion, one billion, two hundred twenty-one million, two hundred ten thousand, one hundred forty-three".
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