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20012213143 = 134732753213
BaseRepresentation
bin10010101000110100…
…100010001110010111
31220122200111202112101
4102220310202032113
5311441111310033
613105443102531
71305631001506
oct225064421627
956580452471
1020012213143
11853a410a2a
123a66071a47
131b6c092950
14d7bb8483d
157c1d7e97d
hex4a8d22397

20012213143 has 8 divisors (see below), whose sum is σ = 22010159808. Its totient is φ = 18079773024.

The previous prime is 20012213141. The next prime is 20012213167. The reversal of 20012213143 is 34131221002.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 20012213143 - 21 = 20012213141 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 20012213143.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20012213141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16375996 + ... + 16377217.

It is an arithmetic number, because the mean of its divisors is an integer number (2751269976).

Almost surely, 220012213143 is an apocalyptic number.

20012213143 is a deficient number, since it is larger than the sum of its proper divisors (1997946665).

20012213143 is a wasteful number, since it uses less digits than its factorization.

20012213143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32753273.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 20012213143 its reverse (34131221002), we get a palindrome (54143434145).

The spelling of 20012213143 in words is "twenty billion, twelve million, two hundred thirteen thousand, one hundred forty-three".

Divisors: 1 13 47 611 32753213 425791769 1539401011 20012213143