Base | Representation |
---|---|
bin | 11101000111110010101… |
… | …110101000011011001111 |
3 | 21002022112022021011200221 |
4 | 131013302232220123033 |
5 | 230242010404244434 |
6 | 4131204153132211 |
7 | 264404253131314 |
oct | 35076256503317 |
9 | 7068468234627 |
10 | 2001232103119 |
11 | 701799394127 |
12 | 283a286ba067 |
13 | 11693b8b8b82 |
14 | 6cc08378d0b |
15 | 370cb25a2b4 |
hex | 1d1f2ba86cf |
2001232103119 has 4 divisors (see below), whose sum is σ = 2001623050240. Its totient is φ = 2000841156000.
The previous prime is 2001232103047. The next prime is 2001232103147. The reversal of 2001232103119 is 9113012321002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2001232103119 - 29 = 2001232102607 is a prime.
It is a super-2 number, since 2×20012321031192 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2001232103093 and 2001232103102.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2001232103219) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 195465882 + ... + 195476119.
It is an arithmetic number, because the mean of its divisors is an integer number (500405762560).
Almost surely, 22001232103119 is an apocalyptic number.
2001232103119 is a deficient number, since it is larger than the sum of its proper divisors (390947121).
2001232103119 is an equidigital number, since it uses as much as digits as its factorization.
2001232103119 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 390947120.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 2001232103119 in words is "two trillion, one billion, two hundred thirty-two million, one hundred three thousand, one hundred nineteen".
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