Base | Representation |
---|---|
bin | 1001000110011011110111… |
… | …10100100001111100000001 |
3 | 2121212011022200112102002012 |
4 | 10203031323310201330001 |
5 | 10110340222440001004 |
6 | 110321312032502305 |
7 | 4133562123214055 |
oct | 443157364417401 |
9 | 77764280472065 |
10 | 20012330000129 |
11 | 64161aa623695 |
12 | 22b26349aa995 |
13 | b2220191b3bc |
14 | 4d285da1bc65 |
15 | 24a87758e46e |
hex | 12337bd21f01 |
20012330000129 has 2 divisors, whose sum is σ = 20012330000130. Its totient is φ = 20012330000128.
The previous prime is 20012330000059. The next prime is 20012330000141. The reversal of 20012330000129 is 92100003321002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13464606442225 + 6547723557904 = 3669415^2 + 2558852^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20012330000129 is a prime.
It is a super-2 number, since 2×200123300001292 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20012330000629) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10006165000064 + 10006165000065.
It is an arithmetic number, because the mean of its divisors is an integer number (10006165000065).
Almost surely, 220012330000129 is an apocalyptic number.
It is an amenable number.
20012330000129 is a deficient number, since it is larger than the sum of its proper divisors (1).
20012330000129 is an equidigital number, since it uses as much as digits as its factorization.
20012330000129 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
The spelling of 20012330000129 in words is "twenty trillion, twelve billion, three hundred thirty million, one hundred twenty-nine", and thus it is an aban number.
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