20012330000141 has 2 divisors, whose sum is σ = 20012330000142. Its totient is φ = 20012330000140.

The previous prime is 20012330000129. The next prime is 20012330000161. The reversal of 20012330000141 is 14100003321002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10103974755625 + 9908355244516 = 3178675^2 + 3147754^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-20012330000141 is a prime.

It is a super-3 number, since 3×20012330000141³ (a number of 41 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20012330000161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10006165000070 + 10006165000071.

It is an arithmetic number, because the mean of its divisors is an integer number (10006165000071).

Almost surely, 2^{20012330000141} is an apocalyptic number.

It is an amenable number.

20012330000141 is a deficient number, since it is larger than the sum of its proper divisors (1).

20012330000141 is an equidigital number, since it uses as much as digits as its factorization.

20012330000141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 20012330000141 its reverse (14100003321002), we get a palindrome (34112333321143).

The spelling of 20012330000141 in words is "twenty trillion, twelve billion, three hundred thirty million, one hundred forty-one", and thus it is an aban number.