Base | Representation |
---|---|
bin | 11101000111110010110… |
… | …010001011001101001101 |
3 | 21002022112101000100220102 |
4 | 131013302302023031031 |
5 | 230242011124011023 |
6 | 4131204225100445 |
7 | 264404264050415 |
oct | 35076262131515 |
9 | 7068471010812 |
10 | 2001233032013 |
11 | 701799969006 |
12 | 283a28a87725 |
13 | 11693bb52907 |
14 | 6cc0853b645 |
15 | 370cb390628 |
hex | 1d1f2c8b34d |
2001233032013 has 2 divisors, whose sum is σ = 2001233032014. Its totient is φ = 2001233032012.
The previous prime is 2001233032009. The next prime is 2001233032087. The reversal of 2001233032013 is 3102303321002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1998499624489 + 2733407524 = 1413683^2 + 52282^2 .
It is a cyclic number.
It is not a de Polignac number, because 2001233032013 - 22 = 2001233032009 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2001233032613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000616516006 + 1000616516007.
It is an arithmetic number, because the mean of its divisors is an integer number (1000616516007).
Almost surely, 22001233032013 is an apocalyptic number.
It is an amenable number.
2001233032013 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001233032013 is an equidigital number, since it uses as much as digits as its factorization.
2001233032013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 20.
Adding to 2001233032013 its reverse (3102303321002), we get a palindrome (5103536353015).
The spelling of 2001233032013 in words is "two trillion, one billion, two hundred thirty-three million, thirty-two thousand, thirteen".
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