Base | Representation |
---|---|
bin | 1001000110011101001110… |
… | …00100010110001001000011 |
3 | 2121212020012020210222220011 |
4 | 10203032213010112021003 |
5 | 10110343214211111103 |
6 | 110321512032125351 |
7 | 4133616113346454 |
oct | 443164704261103 |
9 | 77766166728804 |
10 | 20013055566403 |
11 | 6416542145339 |
12 | 22b27b7996857 |
13 | b222b903c663 |
14 | 4d28cc12d12b |
15 | 24a8bb111d6d |
hex | 1233a7116243 |
20013055566403 has 2 divisors, whose sum is σ = 20013055566404. Its totient is φ = 20013055566402.
The previous prime is 20013055566401. The next prime is 20013055566533. The reversal of 20013055566403 is 30466555031002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20013055566403 - 21 = 20013055566401 is a prime.
It is a super-3 number, since 3×200130555664033 (a number of 41 digits) contains 333 as substring.
Together with 20013055566401, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (20013055566401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10006527783201 + 10006527783202.
It is an arithmetic number, because the mean of its divisors is an integer number (10006527783202).
Almost surely, 220013055566403 is an apocalyptic number.
20013055566403 is a deficient number, since it is larger than the sum of its proper divisors (1).
20013055566403 is an equidigital number, since it uses as much as digits as its factorization.
20013055566403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324000, while the sum is 40.
The spelling of 20013055566403 in words is "twenty trillion, thirteen billion, fifty-five million, five hundred sixty-six thousand, four hundred three".
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