Base | Representation |
---|---|
bin | 101101100000010010100001… |
… | …111101100101111011010011 |
3 | 222020121100010102110110211121 |
4 | 231200102201331211323103 |
5 | 202212421303412333243 |
6 | 1545350530205223111 |
7 | 60103663036002553 |
oct | 5540224175457323 |
9 | 866540112413747 |
10 | 200131013402323 |
11 | 5884a0a472a663 |
12 | 1a542893561a97 |
13 | 87893730b3c53 |
14 | 375c56d929163 |
15 | 1820d00d801ed |
hex | b604a1f65ed3 |
200131013402323 has 2 divisors, whose sum is σ = 200131013402324. Its totient is φ = 200131013402322.
The previous prime is 200131013402233. The next prime is 200131013402351. The reversal of 200131013402323 is 323204310131002.
Together with previous prime (200131013402233) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200131013402323 - 229 = 200130476531411 is a prime.
It is not a weakly prime, because it can be changed into another prime (200131013402363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100065506701161 + 100065506701162.
It is an arithmetic number, because the mean of its divisors is an integer number (100065506701162).
Almost surely, 2200131013402323 is an apocalyptic number.
200131013402323 is a deficient number, since it is larger than the sum of its proper divisors (1).
200131013402323 is an equidigital number, since it uses as much as digits as its factorization.
200131013402323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 200131013402323 its reverse (323204310131002), we get a palindrome (523335323533325).
The spelling of 200131013402323 in words is "two hundred trillion, one hundred thirty-one billion, thirteen million, four hundred two thousand, three hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •