Base | Representation |
---|---|
bin | 101101100000010010101101… |
… | …111000001100001111000111 |
3 | 222020121100122100121222200112 |
4 | 231200102231320030033013 |
5 | 202212422211102003332 |
6 | 1545351002110103235 |
7 | 60104001014135456 |
oct | 5540225570141707 |
9 | 866540570558615 |
10 | 200131213312967 |
11 | 5884a197561472 |
12 | 1a54292a4aab1b |
13 | 87893a5639681 |
14 | 375c58c2c6b9d |
15 | 1820d136bcdb2 |
hex | b604ade0c3c7 |
200131213312967 has 2 divisors, whose sum is σ = 200131213312968. Its totient is φ = 200131213312966.
The previous prime is 200131213312963. The next prime is 200131213313011. The reversal of 200131213312967 is 769213312131002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200131213312967 - 22 = 200131213312963 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200131213312963) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100065606656483 + 100065606656484.
It is an arithmetic number, because the mean of its divisors is an integer number (100065606656484).
Almost surely, 2200131213312967 is an apocalyptic number.
200131213312967 is a deficient number, since it is larger than the sum of its proper divisors (1).
200131213312967 is an equidigital number, since it uses as much as digits as its factorization.
200131213312967 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81648, while the sum is 41.
Adding to 200131213312967 its reverse (769213312131002), we get a palindrome (969344525443969).
The spelling of 200131213312967 in words is "two hundred trillion, one hundred thirty-one billion, two hundred thirteen million, three hundred twelve thousand, nine hundred sixty-seven".
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