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20013141977 is a prime number
BaseRepresentation
bin10010101000111000…
…000100111111011001
31220122202020221122122
4102220320010333121
5311441331020402
613105515031025
71305641620463
oct225070047731
956582227578
1020013141977
11853a995864
123a6643b475
131b6c32965a
14d7bd47133
157c1eb4ca2
hex4a8e04fd9

20013141977 has 2 divisors, whose sum is σ = 20013141978. Its totient is φ = 20013141976.

The previous prime is 20013141971. The next prime is 20013141979. The reversal of 20013141977 is 77914131002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10761780121 + 9251361856 = 103739^2 + 96184^2 .

It is a cyclic number.

It is not a de Polignac number, because 20013141977 - 28 = 20013141721 is a prime.

Together with 20013141979, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (20013141971) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10006570988 + 10006570989.

It is an arithmetic number, because the mean of its divisors is an integer number (10006570989).

Almost surely, 220013141977 is an apocalyptic number.

It is an amenable number.

20013141977 is a deficient number, since it is larger than the sum of its proper divisors (1).

20013141977 is an equidigital number, since it uses as much as digits as its factorization.

20013141977 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10584, while the sum is 35.

Adding to 20013141977 its reverse (77914131002), we get a palindrome (97927272979).

The spelling of 20013141977 in words is "twenty billion, thirteen million, one hundred forty-one thousand, nine hundred seventy-seven".