Base | Representation |
---|---|
bin | 1001000110011101011011… |
… | …11111100111100101011111 |
3 | 2121212020111100110122000221 |
4 | 10203032231333213211133 |
5 | 10110343433433031042 |
6 | 110321531342502211 |
7 | 4133622024136552 |
oct | 443165577474537 |
9 | 77766440418027 |
10 | 20013171767647 |
11 | 64165a17a2023 |
12 | 22b282a894967 |
13 | b223071364a6 |
14 | 4d28dd73a699 |
15 | 24a8c6416d67 |
hex | 1233adfe795f |
20013171767647 has 2 divisors, whose sum is σ = 20013171767648. Its totient is φ = 20013171767646.
The previous prime is 20013171767557. The next prime is 20013171767711. The reversal of 20013171767647 is 74676717131002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20013171767647 - 223 = 20013163379039 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20013171767594 and 20013171767603.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20013171768647) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10006585883823 + 10006585883824.
It is an arithmetic number, because the mean of its divisors is an integer number (10006585883824).
Almost surely, 220013171767647 is an apocalyptic number.
20013171767647 is a deficient number, since it is larger than the sum of its proper divisors (1).
20013171767647 is an equidigital number, since it uses as much as digits as its factorization.
20013171767647 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2074464, while the sum is 52.
Adding to 20013171767647 its reverse (74676717131002), we get a palindrome (94689888898649).
The spelling of 20013171767647 in words is "twenty trillion, thirteen billion, one hundred seventy-one million, seven hundred sixty-seven thousand, six hundred forty-seven".
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