20013311130031 has 2 divisors, whose sum is σ = 20013311130032. Its totient is φ = 20013311130030.

The previous prime is 20013311129971. The next prime is 20013311130061. The reversal of 20013311130031 is 13003111331002.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 20013311130031 - 2²³ = 20013302741423 is a prime.

It is a super-4 number, since 4×20013311130031⁴ (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 20013311129990 and 20013311130008.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20013311130061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10006655565015 + 10006655565016.

It is an arithmetic number, because the mean of its divisors is an integer number (10006655565016).

Almost surely, 2^{20013311130031} is an apocalyptic number.

20013311130031 is a deficient number, since it is larger than the sum of its proper divisors (1).

20013311130031 is an equidigital number, since it uses as much as digits as its factorization.

20013311130031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 20013311130031 its reverse (13003111331002), we get a palindrome (33016422461033).

The spelling of 20013311130031 in words is "twenty trillion, thirteen billion, three hundred eleven million, one hundred thirty thousand, thirty-one".