Base | Representation |
---|---|
bin | 1001000110011101110111… |
… | …10111001111010100011111 |
3 | 2121212021002120022020010122 |
4 | 10203032323313033110133 |
5 | 10110344423014432002 |
6 | 110322010414025155 |
7 | 4133630551003142 |
oct | 443167367172437 |
9 | 77767076266118 |
10 | 20013404452127 |
11 | 6416701079349 |
12 | 22b28947a81bb |
13 | b223433c5608 |
14 | 4d29225ca059 |
15 | 24a8dba7a6a2 |
hex | 1233bbdcf51f |
20013404452127 has 2 divisors, whose sum is σ = 20013404452128. Its totient is φ = 20013404452126.
The previous prime is 20013404452099. The next prime is 20013404452133. The reversal of 20013404452127 is 72125440431002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20013404452127 - 28 = 20013404451871 is a prime.
It is a super-3 number, since 3×200134044521273 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20013404452177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10006702226063 + 10006702226064.
It is an arithmetic number, because the mean of its divisors is an integer number (10006702226064).
Almost surely, 220013404452127 is an apocalyptic number.
20013404452127 is a deficient number, since it is larger than the sum of its proper divisors (1).
20013404452127 is an equidigital number, since it uses as much as digits as its factorization.
20013404452127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 53760, while the sum is 35.
Adding to 20013404452127 its reverse (72125440431002), we get a palindrome (92138844883129).
The spelling of 20013404452127 in words is "twenty trillion, thirteen billion, four hundred four million, four hundred fifty-two thousand, one hundred twenty-seven".
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