20013653425003 has 32 divisors (see below), whose sum is σ = 23035137840000. Its totient is φ = 17033218375680.

The previous prime is 20013653424991. The next prime is 20013653425019. The reversal of 20013653425003 is 30052435631002.

It is a cyclic number.

It is not a de Polignac number, because 20013653425003 - 2⁹ = 20013653424491 is a prime.

It is a super-4 number, since 4×20013653425003⁴ (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 20013653425003.

It is not an unprimeable number, because it can be changed into a prime (20013653425093) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3103369923 + ... + 3103376371.

It is an arithmetic number, because the mean of its divisors is an integer number (719848057500).

Almost surely, 2^{20013653425003} is an apocalyptic number.

20013653425003 is a deficient number, since it is larger than the sum of its proper divisors (3021484414997).

20013653425003 is a wasteful number, since it uses less digits than its factorization.

20013653425003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11815.

The product of its (nonzero) digits is 64800, while the sum is 34.

The spelling of 20013653425003 in words is "twenty trillion, thirteen billion, six hundred fifty-three million, four hundred twenty-five thousand, three".