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20013653449411 is a prime number
BaseRepresentation
bin1001000110011110010101…
…01101000101101011000011
32121212021201220211121012021
410203033022231011223003
510110400430240340121
6110322051230542311
74133636663310556
oct443171255055303
977767656747167
1020013653449411
116416819687726
1222b2944067997
13b22382b7679b
144d29476c469d
1524a903862641
hex1233cab45ac3

20013653449411 has 2 divisors, whose sum is σ = 20013653449412. Its totient is φ = 20013653449410.

The previous prime is 20013653449409. The next prime is 20013653449441. The reversal of 20013653449411 is 11494435631002.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 20013653449411 - 21 = 20013653449409 is a prime.

Together with 20013653449409, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (20013653449441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10006826724705 + 10006826724706.

It is an arithmetic number, because the mean of its divisors is an integer number (10006826724706).

Almost surely, 220013653449411 is an apocalyptic number.

20013653449411 is a deficient number, since it is larger than the sum of its proper divisors (1).

20013653449411 is an equidigital number, since it uses as much as digits as its factorization.

20013653449411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 311040, while the sum is 43.

The spelling of 20013653449411 in words is "twenty trillion, thirteen billion, six hundred fifty-three million, four hundred forty-nine thousand, four hundred eleven".