Base | Representation |
---|---|
bin | 1001000110011110010101… |
… | …01101000101101011000011 |
3 | 2121212021201220211121012021 |
4 | 10203033022231011223003 |
5 | 10110400430240340121 |
6 | 110322051230542311 |
7 | 4133636663310556 |
oct | 443171255055303 |
9 | 77767656747167 |
10 | 20013653449411 |
11 | 6416819687726 |
12 | 22b2944067997 |
13 | b22382b7679b |
14 | 4d29476c469d |
15 | 24a903862641 |
hex | 1233cab45ac3 |
20013653449411 has 2 divisors, whose sum is σ = 20013653449412. Its totient is φ = 20013653449410.
The previous prime is 20013653449409. The next prime is 20013653449441. The reversal of 20013653449411 is 11494435631002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20013653449411 - 21 = 20013653449409 is a prime.
Together with 20013653449409, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (20013653449441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10006826724705 + 10006826724706.
It is an arithmetic number, because the mean of its divisors is an integer number (10006826724706).
Almost surely, 220013653449411 is an apocalyptic number.
20013653449411 is a deficient number, since it is larger than the sum of its proper divisors (1).
20013653449411 is an equidigital number, since it uses as much as digits as its factorization.
20013653449411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 311040, while the sum is 43.
The spelling of 20013653449411 in words is "twenty trillion, thirteen billion, six hundred fifty-three million, four hundred forty-nine thousand, four hundred eleven".
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