Base | Representation |
---|---|
bin | 101101100000011011000010… |
… | …001100100111000001100011 |
3 | 222020122012200202120020101011 |
4 | 231200123002030213001203 |
5 | 202213044003400110413 |
6 | 1545355040220521351 |
7 | 60104435230015234 |
oct | 5540330214470143 |
9 | 866565622506334 |
10 | 200140144144483 |
11 | 58852a5a7aa364 |
12 | 1a5446013b0257 |
13 | 878a19997c76a |
14 | 375cb9845508b |
15 | 182118778533d |
hex | b606c2327063 |
200140144144483 has 2 divisors, whose sum is σ = 200140144144484. Its totient is φ = 200140144144482.
The previous prime is 200140144144433. The next prime is 200140144144531. The reversal of 200140144144483 is 384441441041002.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200140144144483 - 225 = 200140110590051 is a prime.
It is not a weakly prime, because it can be changed into another prime (200140144144433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100070072072241 + 100070072072242.
It is an arithmetic number, because the mean of its divisors is an integer number (100070072072242).
Almost surely, 2200140144144483 is an apocalyptic number.
200140144144483 is a deficient number, since it is larger than the sum of its proper divisors (1).
200140144144483 is an equidigital number, since it uses as much as digits as its factorization.
200140144144483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 196608, while the sum is 40.
Adding to 200140144144483 its reverse (384441441041002), we get a palindrome (584581585185485).
The spelling of 200140144144483 in words is "two hundred trillion, one hundred forty billion, one hundred forty-four million, one hundred forty-four thousand, four hundred eighty-three".
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