Base | Representation |
---|---|
bin | 101101100000011011000101… |
… | …001000011001101101000001 |
3 | 222020122012211012012022012022 |
4 | 231200123011020121231001 |
5 | 202213044104000413433 |
6 | 1545355045140011225 |
7 | 60104436365320466 |
oct | 5540330510315501 |
9 | 866565735168168 |
10 | 200140193372993 |
11 | 58852a85573485 |
12 | 1a544615990b15 |
13 | 878a1a6c27963 |
14 | 375cba0bcb66d |
15 | 182118bc5b698 |
hex | b606c5219b41 |
200140193372993 has 2 divisors, whose sum is σ = 200140193372994. Its totient is φ = 200140193372992.
The previous prime is 200140193372989. The next prime is 200140193373139. The reversal of 200140193372993 is 399273391041002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 152063623262464 + 48076570110529 = 12331408^2 + 6933727^2 .
It is a cyclic number.
It is not a de Polignac number, because 200140193372993 - 22 = 200140193372989 is a prime.
It is not a weakly prime, because it can be changed into another prime (200140193372923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100070096686496 + 100070096686497.
It is an arithmetic number, because the mean of its divisors is an integer number (100070096686497).
Almost surely, 2200140193372993 is an apocalyptic number.
It is an amenable number.
200140193372993 is a deficient number, since it is larger than the sum of its proper divisors (1).
200140193372993 is an equidigital number, since it uses as much as digits as its factorization.
200140193372993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2204496, while the sum is 53.
The spelling of 200140193372993 in words is "two hundred trillion, one hundred forty billion, one hundred ninety-three million, three hundred seventy-two thousand, nine hundred ninety-three".
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