Base | Representation |
---|---|
bin | 101101100000011011001000… |
… | …110101100001000011011111 |
3 | 222020122012222112011021021021 |
4 | 231200123020311201003133 |
5 | 202213044220403444411 |
6 | 1545355055240145011 |
7 | 60104441051544031 |
oct | 5540331065410337 |
9 | 866565875137237 |
10 | 200140255531231 |
11 | 58853007668924 |
12 | 1a544632768167 |
13 | 878a1b6a7c092 |
14 | 375cba916bc51 |
15 | 1821192438a71 |
hex | b606c8d610df |
200140255531231 has 32 divisors (see below), whose sum is σ = 208037249925120. Its totient is φ = 192338634240000.
The previous prime is 200140255531217. The next prime is 200140255531253. The reversal of 200140255531231 is 132135552041002.
It is a cyclic number.
It is not a de Polignac number, because 200140255531231 - 25 = 200140255531199 is a prime.
It is a super-2 number, since 2×2001402555312312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200140255531211) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4297321861 + ... + 4297368433.
It is an arithmetic number, because the mean of its divisors is an integer number (6501164060160).
Almost surely, 2200140255531231 is an apocalyptic number.
200140255531231 is a deficient number, since it is larger than the sum of its proper divisors (7896994393889).
200140255531231 is a wasteful number, since it uses less digits than its factorization.
200140255531231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 48487.
The product of its (nonzero) digits is 36000, while the sum is 34.
The spelling of 200140255531231 in words is "two hundred trillion, one hundred forty billion, two hundred fifty-five million, five hundred thirty-one thousand, two hundred thirty-one".
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