20014051127341 has 2 divisors, whose sum is σ = 20014051127342. Its totient is φ = 20014051127340.

The previous prime is 20014051127281. The next prime is 20014051127359. The reversal of 20014051127341 is 14372115041002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16018965616900 + 3995085510441 = 4002370^2 + 1998771^2 .

It is a cyclic number.

It is not a de Polignac number, because 20014051127341 - 2⁴¹ = 17815027871789 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20014051127041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10007025563670 + 10007025563671.

It is an arithmetic number, because the mean of its divisors is an integer number (10007025563671).

Almost surely, 2^{20014051127341} is an apocalyptic number.

It is an amenable number.

20014051127341 is a deficient number, since it is larger than the sum of its proper divisors (1).

20014051127341 is an equidigital number, since it uses as much as digits as its factorization.

20014051127341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6720, while the sum is 31.

Adding to 20014051127341 its reverse (14372115041002), we get a palindrome (34386166168343).

The spelling of 20014051127341 in words is "twenty trillion, fourteen billion, fifty-one million, one hundred twenty-seven thousand, three hundred forty-one".