Base | Representation |
---|---|
bin | 11101000111111101011… |
… | …100111101111101000011 |
3 | 21002022222211211000010021 |
4 | 131013331130331331003 |
5 | 230242342434201313 |
6 | 4131234101314311 |
7 | 264411566331355 |
oct | 35077534757503 |
9 | 7068884730107 |
10 | 2001412022083 |
11 | 701880a00991 |
12 | 283a78a05997 |
13 | 116969c61bb6 |
14 | 6cc242110d5 |
15 | 370dbe4978d |
hex | 1d1fd73df43 |
2001412022083 has 2 divisors, whose sum is σ = 2001412022084. Its totient is φ = 2001412022082.
The previous prime is 2001412022059. The next prime is 2001412022119. The reversal of 2001412022083 is 3802202141002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2001412022083 - 213 = 2001412013891 is a prime.
It is not a weakly prime, because it can be changed into another prime (2001412022033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000706011041 + 1000706011042.
It is an arithmetic number, because the mean of its divisors is an integer number (1000706011042).
Almost surely, 22001412022083 is an apocalyptic number.
2001412022083 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001412022083 is an equidigital number, since it uses as much as digits as its factorization.
2001412022083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 2001412022083 its reverse (3802202141002), we get a palindrome (5803614163085).
The spelling of 2001412022083 in words is "two trillion, one billion, four hundred twelve million, twenty-two thousand, eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •