Base | Representation |
---|---|
bin | 101101100000011100001101… |
… | …001101010100110100001011 |
3 | 222020122022221110121120200121 |
4 | 231200130031031110310023 |
5 | 202213104043032420433 |
6 | 1545355405134244111 |
7 | 60104511350633434 |
oct | 5540341515246413 |
9 | 866568843546617 |
10 | 200141402623243 |
11 | 58853546118054 |
12 | 1a5448b2956637 |
13 | 878a33a60a653 |
14 | 375cc7764848b |
15 | 182120cec2c2d |
hex | b6070d354d0b |
200141402623243 has 2 divisors, whose sum is σ = 200141402623244. Its totient is φ = 200141402623242.
The previous prime is 200141402623213. The next prime is 200141402623247. The reversal of 200141402623243 is 342326204141002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200141402623243 - 221 = 200141400526091 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 200141402623199 and 200141402623208.
It is not a weakly prime, because it can be changed into another prime (200141402623247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100070701311621 + 100070701311622.
It is an arithmetic number, because the mean of its divisors is an integer number (100070701311622).
Almost surely, 2200141402623243 is an apocalyptic number.
200141402623243 is a deficient number, since it is larger than the sum of its proper divisors (1).
200141402623243 is an equidigital number, since it uses as much as digits as its factorization.
200141402623243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 34.
Adding to 200141402623243 its reverse (342326204141002), we get a palindrome (542467606764245).
The spelling of 200141402623243 in words is "two hundred trillion, one hundred forty-one billion, four hundred two million, six hundred twenty-three thousand, two hundred forty-three".
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