Base | Representation |
---|---|
bin | 11101000111111110000… |
… | …011100010011111001101 |
3 | 21002100000112211200221222 |
4 | 131013332003202133031 |
5 | 230242403031230242 |
6 | 4131235102133125 |
7 | 264412051303004 |
oct | 35077603423715 |
9 | 7070015750858 |
10 | 2001422133197 |
11 | 701886687583 |
12 | 283a802811a5 |
13 | 11696c0921c6 |
14 | 6cc256c3c3b |
15 | 370dcc955d2 |
hex | 1d1fe0e27cd |
2001422133197 has 2 divisors, whose sum is σ = 2001422133198. Its totient is φ = 2001422133196.
The previous prime is 2001422133187. The next prime is 2001422133229. The reversal of 2001422133197 is 7913312241002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1102539900361 + 898882232836 = 1050019^2 + 948094^2 .
It is a cyclic number.
It is not a de Polignac number, because 2001422133197 - 234 = 1984242264013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2001422133107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000711066598 + 1000711066599.
It is an arithmetic number, because the mean of its divisors is an integer number (1000711066599).
Almost surely, 22001422133197 is an apocalyptic number.
It is an amenable number.
2001422133197 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001422133197 is an equidigital number, since it uses as much as digits as its factorization.
2001422133197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 35.
Adding to 2001422133197 its reverse (7913312241002), we get a palindrome (9914734374199).
The spelling of 2001422133197 in words is "two trillion, one billion, four hundred twenty-two million, one hundred thirty-three thousand, one hundred ninety-seven".
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