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2001422133197 is a prime number
BaseRepresentation
bin11101000111111110000…
…011100010011111001101
321002100000112211200221222
4131013332003202133031
5230242403031230242
64131235102133125
7264412051303004
oct35077603423715
97070015750858
102001422133197
11701886687583
12283a802811a5
1311696c0921c6
146cc256c3c3b
15370dcc955d2
hex1d1fe0e27cd

2001422133197 has 2 divisors, whose sum is σ = 2001422133198. Its totient is φ = 2001422133196.

The previous prime is 2001422133187. The next prime is 2001422133229. The reversal of 2001422133197 is 7913312241002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1102539900361 + 898882232836 = 1050019^2 + 948094^2 .

It is a cyclic number.

It is not a de Polignac number, because 2001422133197 - 234 = 1984242264013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2001422133107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000711066598 + 1000711066599.

It is an arithmetic number, because the mean of its divisors is an integer number (1000711066599).

Almost surely, 22001422133197 is an apocalyptic number.

It is an amenable number.

2001422133197 is a deficient number, since it is larger than the sum of its proper divisors (1).

2001422133197 is an equidigital number, since it uses as much as digits as its factorization.

2001422133197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18144, while the sum is 35.

Adding to 2001422133197 its reverse (7913312241002), we get a palindrome (9914734374199).

The spelling of 2001422133197 in words is "two trillion, one billion, four hundred twenty-two million, one hundred thirty-three thousand, one hundred ninety-seven".