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200143040213 is a prime number
BaseRepresentation
bin1011101001100101110…
…1000110111011010101
3201010121022102212210002
42322121131012323111
511234343104241323
6231535555541045
720313505525604
oct2723135067325
9633538385702
10200143040213
117797558a456
12329575ba785
1315b47b5225c
1499890b7a3b
155315ccb828
hex2e99746ed5

200143040213 has 2 divisors, whose sum is σ = 200143040214. Its totient is φ = 200143040212.

The previous prime is 200143040173. The next prime is 200143040219. The reversal of 200143040213 is 312040341002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 189954762244 + 10188277969 = 435838^2 + 100937^2 .

It is a cyclic number.

It is not a de Polignac number, because 200143040213 - 210 = 200143039189 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200143040219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100071520106 + 100071520107.

It is an arithmetic number, because the mean of its divisors is an integer number (100071520107).

Almost surely, 2200143040213 is an apocalyptic number.

It is an amenable number.

200143040213 is a deficient number, since it is larger than the sum of its proper divisors (1).

200143040213 is an equidigital number, since it uses as much as digits as its factorization.

200143040213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 200143040213 its reverse (312040341002), we get a palindrome (512183381215).

The spelling of 200143040213 in words is "two hundred billion, one hundred forty-three million, forty thousand, two hundred thirteen".