Base | Representation |
---|---|
bin | 101101100000011101111111… |
… | …011111101000010101011001 |
3 | 222020122111220002112122121121 |
4 | 231200131333133220111121 |
5 | 202213122004411240114 |
6 | 1545400323311005241 |
7 | 60104610022366336 |
oct | 5540357737502531 |
9 | 866574802478547 |
10 | 200143320024409 |
11 | 5885433a478a13 |
12 | 1a545148b09821 |
13 | 878a584924758 |
14 | 375cdba16198d |
15 | 18212c14bba24 |
hex | b6077f7e8559 |
200143320024409 has 2 divisors, whose sum is σ = 200143320024410. Its totient is φ = 200143320024408.
The previous prime is 200143320024121. The next prime is 200143320024433. The reversal of 200143320024409 is 904420023341002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 179473312465225 + 20670007559184 = 13396765^2 + 4546428^2 .
It is a cyclic number.
It is not a de Polignac number, because 200143320024409 - 211 = 200143320022361 is a prime.
It is not a weakly prime, because it can be changed into another prime (200143320024709) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100071660012204 + 100071660012205.
It is an arithmetic number, because the mean of its divisors is an integer number (100071660012205).
Almost surely, 2200143320024409 is an apocalyptic number.
It is an amenable number.
200143320024409 is a deficient number, since it is larger than the sum of its proper divisors (1).
200143320024409 is an equidigital number, since it uses as much as digits as its factorization.
200143320024409 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 34.
The spelling of 200143320024409 in words is "two hundred trillion, one hundred forty-three billion, three hundred twenty million, twenty-four thousand, four hundred nine".
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