Base | Representation |
---|---|
bin | 10010101000111100… |
… | …100111111100101101 |
3 | 1220122211111111110001 |
4 | 102220330213330231 |
5 | 311442132134431 |
6 | 13110000344301 |
7 | 1305655013143 |
oct | 225074477455 |
9 | 56584444401 |
10 | 20014333741 |
11 | 854062a196 |
12 | 3a66915091 |
13 | 1b6c655c3c |
14 | d7c177593 |
15 | 7c214ce61 |
hex | 4a8f27f2d |
20014333741 has 2 divisors, whose sum is σ = 20014333742. Its totient is φ = 20014333740.
The previous prime is 20014333727. The next prime is 20014333771. The reversal of 20014333741 is 14733341002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 19545438025 + 468895716 = 139805^2 + 21654^2 .
It is a cyclic number.
It is not a de Polignac number, because 20014333741 - 25 = 20014333709 is a prime.
It is a super-2 number, since 2×200143337412 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20014333771) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10007166870 + 10007166871.
It is an arithmetic number, because the mean of its divisors is an integer number (10007166871).
Almost surely, 220014333741 is an apocalyptic number.
It is an amenable number.
20014333741 is a deficient number, since it is larger than the sum of its proper divisors (1).
20014333741 is an equidigital number, since it uses as much as digits as its factorization.
20014333741 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 28.
Adding to 20014333741 its reverse (14733341002), we get a palindrome (34747674743).
The spelling of 20014333741 in words is "twenty billion, fourteen million, three hundred thirty-three thousand, seven hundred forty-one".
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