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2001443132407 is a prime number
BaseRepresentation
bin11101000111111111010…
…011101001001111110111
321002100002000100120110111
4131013333103221033313
5230242423420214112
64131241132203451
7264412424633125
oct35077723511767
97070060316414
102001443132407
1170189751a5a4
12283a87309587
13116973535384
146cc283cc915
15370dea425a7
hex1d1ff4e93f7

2001443132407 has 2 divisors, whose sum is σ = 2001443132408. Its totient is φ = 2001443132406.

The previous prime is 2001443132401. The next prime is 2001443132459. The reversal of 2001443132407 is 7042313441002.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2001443132407 - 231 = 1999295648759 is a prime.

It is a super-2 number, since 2×20014431324072 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2001443132401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000721566203 + 1000721566204.

It is an arithmetic number, because the mean of its divisors is an integer number (1000721566204).

Almost surely, 22001443132407 is an apocalyptic number.

2001443132407 is a deficient number, since it is larger than the sum of its proper divisors (1).

2001443132407 is an equidigital number, since it uses as much as digits as its factorization.

2001443132407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16128, while the sum is 31.

Adding to 2001443132407 its reverse (7042313441002), we get a palindrome (9043756573409).

The spelling of 2001443132407 in words is "two trillion, one billion, four hundred forty-three million, one hundred thirty-two thousand, four hundred seven".