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20014467757433 is a prime number
BaseRepresentation
bin1001000110011111110110…
…01111011011010101111001
32121212100211200002201210122
410203033323033123111321
510110404112221214213
6110322304120223025
74133666111645462
oct443177317332571
977770750081718
1020014467757433
1164170a7300366
1222b2b3090aa75
13b22482799056
144d29c38d5d69
1524a9500b3d08
hex1233fb3db579

20014467757433 has 2 divisors, whose sum is σ = 20014467757434. Its totient is φ = 20014467757432.

The previous prime is 20014467757423. The next prime is 20014467757441. The reversal of 20014467757433 is 33475776441002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18722262647929 + 1292205109504 = 4326923^2 + 1136752^2 .

It is a cyclic number.

It is not a de Polignac number, because 20014467757433 - 214 = 20014467741049 is a prime.

It is a super-2 number, since 2×200144677574332 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (20014467757423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10007233878716 + 10007233878717.

It is an arithmetic number, because the mean of its divisors is an integer number (10007233878717).

Almost surely, 220014467757433 is an apocalyptic number.

It is an amenable number.

20014467757433 is a deficient number, since it is larger than the sum of its proper divisors (1).

20014467757433 is an equidigital number, since it uses as much as digits as its factorization.

20014467757433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11854080, while the sum is 53.

The spelling of 20014467757433 in words is "twenty trillion, fourteen billion, four hundred sixty-seven million, seven hundred fifty-seven thousand, four hundred thirty-three".