Base | Representation |
---|---|
bin | 101101100000101000000010… |
… | …111001011000001111010001 |
3 | 222020200112202101022001102221 |
4 | 231200220002321120033101 |
5 | 202213311111304232423 |
6 | 1545405310354341041 |
7 | 60105441355206061 |
oct | 5540500271301721 |
9 | 866615671261387 |
10 | 200154114524113 |
11 | 58858979707352 |
12 | 1a54725bb8a781 |
13 | 878b5b50ba399 |
14 | 375d721a1b3a1 |
15 | 1821703eb6e5d |
hex | b60a02e583d1 |
200154114524113 has 2 divisors, whose sum is σ = 200154114524114. Its totient is φ = 200154114524112.
The previous prime is 200154114524107. The next prime is 200154114524209. The reversal of 200154114524113 is 311425411451002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 181590528655809 + 18563585868304 = 13475553^2 + 4308548^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-200154114524113 is a prime.
It is not a weakly prime, because it can be changed into another prime (200154114554113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100077057262056 + 100077057262057.
It is an arithmetic number, because the mean of its divisors is an integer number (100077057262057).
Almost surely, 2200154114524113 is an apocalyptic number.
It is an amenable number.
200154114524113 is a deficient number, since it is larger than the sum of its proper divisors (1).
200154114524113 is an equidigital number, since it uses as much as digits as its factorization.
200154114524113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19200, while the sum is 34.
Adding to 200154114524113 its reverse (311425411451002), we get a palindrome (511579525975115).
The spelling of 200154114524113 in words is "two hundred trillion, one hundred fifty-four billion, one hundred fourteen million, five hundred twenty-four thousand, one hundred thirteen".
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