Base | Representation |
---|---|
bin | 101101100001010101111001… |
… | …001101101111001111110111 |
3 | 222020212020211021122100211221 |
4 | 231201111321031233033313 |
5 | 202220112422104303413 |
6 | 1545444051401411211 |
7 | 60112133334516556 |
oct | 5541257115571767 |
9 | 866766737570757 |
10 | 200203344212983 |
11 | 58877841577231 |
12 | 1a5548baa99b07 |
13 | 879312c3a06b7 |
14 | 3761c71d0dd9d |
15 | 1822b35deb68d |
hex | b6157936f3f7 |
200203344212983 has 2 divisors, whose sum is σ = 200203344212984. Its totient is φ = 200203344212982.
The previous prime is 200203344212903. The next prime is 200203344213007. The reversal of 200203344212983 is 389212443302002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200203344212983 - 213 = 200203344204791 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200203344212903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100101672106491 + 100101672106492.
It is an arithmetic number, because the mean of its divisors is an integer number (100101672106492).
Almost surely, 2200203344212983 is an apocalyptic number.
200203344212983 is a deficient number, since it is larger than the sum of its proper divisors (1).
200203344212983 is an equidigital number, since it uses as much as digits as its factorization.
200203344212983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 497664, while the sum is 43.
Adding to 200203344212983 its reverse (389212443302002), we get a palindrome (589415787514985).
The spelling of 200203344212983 in words is "two hundred trillion, two hundred three billion, three hundred forty-four million, two hundred twelve thousand, nine hundred eighty-three".
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