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200203344244339 is a prime number
BaseRepresentation
bin101101100001010101111001…
…001101110110111001110011
3222020212020211021200221212021
4231201111321031312321303
5202220112422111304324
61545444051402212311
760112133335010152
oct5541257115667163
9866766737627767
10200203344244339
1158877841598847
121a5548baab4097
13879312c3b1a57
143761c71d1b599
151822b35e05ae4
hexb61579376e73

200203344244339 has 2 divisors, whose sum is σ = 200203344244340. Its totient is φ = 200203344244338.

The previous prime is 200203344244307. The next prime is 200203344244429. The reversal of 200203344244339 is 933442443302002.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 200203344244339 - 25 = 200203344244307 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 200203344244295 and 200203344244304.

It is not a weakly prime, because it can be changed into another prime (200203344244139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100101672122169 + 100101672122170.

It is an arithmetic number, because the mean of its divisors is an integer number (100101672122170).

Almost surely, 2200203344244339 is an apocalyptic number.

200203344244339 is a deficient number, since it is larger than the sum of its proper divisors (1).

200203344244339 is an equidigital number, since it uses as much as digits as its factorization.

200203344244339 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1492992, while the sum is 43.

The spelling of 200203344244339 in words is "two hundred trillion, two hundred three billion, three hundred forty-four million, two hundred forty-four thousand, three hundred thirty-nine".