Base | Representation |
---|---|
bin | 1001000110101100000010… |
… | …00100100100100011000101 |
3 | 2121212222201110202210100021 |
4 | 10203112001010210203011 |
5 | 10111011011023311142 |
6 | 110325305113015141 |
7 | 4134320146214332 |
oct | 443260104444305 |
9 | 77788643683307 |
10 | 20021008025797 |
11 | 64199530a1829 |
12 | 22b42570b44b1 |
13 | b22c8577892c |
14 | 4d304437d989 |
15 | 24abd436b267 |
hex | 1235811248c5 |
20021008025797 has 2 divisors, whose sum is σ = 20021008025798. Its totient is φ = 20021008025796.
The previous prime is 20021008025749. The next prime is 20021008025881. The reversal of 20021008025797 is 79752080012002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 20014090111521 + 6917914276 = 4473711^2 + 83174^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20021008025797 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20021018025797) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10010504012898 + 10010504012899.
It is an arithmetic number, because the mean of its divisors is an integer number (10010504012899).
Almost surely, 220021008025797 is an apocalyptic number.
It is an amenable number.
20021008025797 is a deficient number, since it is larger than the sum of its proper divisors (1).
20021008025797 is an equidigital number, since it uses as much as digits as its factorization.
20021008025797 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 141120, while the sum is 43.
Adding to 20021008025797 its reverse (79752080012002), we get a palindrome (99773088037799).
The spelling of 20021008025797 in words is "twenty trillion, twenty-one billion, eight million, twenty-five thousand, seven hundred ninety-seven".
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