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20021008025797 is a prime number
BaseRepresentation
bin1001000110101100000010…
…00100100100100011000101
32121212222201110202210100021
410203112001010210203011
510111011011023311142
6110325305113015141
74134320146214332
oct443260104444305
977788643683307
1020021008025797
1164199530a1829
1222b42570b44b1
13b22c8577892c
144d304437d989
1524abd436b267
hex1235811248c5

20021008025797 has 2 divisors, whose sum is σ = 20021008025798. Its totient is φ = 20021008025796.

The previous prime is 20021008025749. The next prime is 20021008025881. The reversal of 20021008025797 is 79752080012002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 20014090111521 + 6917914276 = 4473711^2 + 83174^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20021008025797 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20021018025797) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10010504012898 + 10010504012899.

It is an arithmetic number, because the mean of its divisors is an integer number (10010504012899).

Almost surely, 220021008025797 is an apocalyptic number.

It is an amenable number.

20021008025797 is a deficient number, since it is larger than the sum of its proper divisors (1).

20021008025797 is an equidigital number, since it uses as much as digits as its factorization.

20021008025797 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 141120, while the sum is 43.

Adding to 20021008025797 its reverse (79752080012002), we get a palindrome (99773088037799).

The spelling of 20021008025797 in words is "twenty trillion, twenty-one billion, eight million, twenty-five thousand, seven hundred ninety-seven".