Base | Representation |
---|---|
bin | 101101100001011100001100… |
… | …100111010000010011001101 |
3 | 222020212220021221122122221021 |
4 | 231201130030213100103031 |
5 | 202220220302200320023 |
6 | 1545451131125234141 |
7 | 60112463135005132 |
oct | 5541341447202315 |
9 | 866786257578837 |
10 | 200210112120013 |
11 | 5887a6a4908a26 |
12 | 1a556089562951 |
13 | 879396a593808 |
14 | 3762314ad2589 |
15 | 1822dd016c35d |
hex | b6170c9d04cd |
200210112120013 has 2 divisors, whose sum is σ = 200210112120014. Its totient is φ = 200210112120012.
The previous prime is 200210112119959. The next prime is 200210112120037. The reversal of 200210112120013 is 310021211012002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 134169085927044 + 66041026192969 = 11583138^2 + 8126563^2 .
It is a cyclic number.
It is not a de Polignac number, because 200210112120013 - 233 = 200201522185421 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200210112121013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100105056060006 + 100105056060007.
It is an arithmetic number, because the mean of its divisors is an integer number (100105056060007).
Almost surely, 2200210112120013 is an apocalyptic number.
It is an amenable number.
200210112120013 is a deficient number, since it is larger than the sum of its proper divisors (1).
200210112120013 is an equidigital number, since it uses as much as digits as its factorization.
200210112120013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 200210112120013 its reverse (310021211012002), we get a palindrome (510231323132015).
The spelling of 200210112120013 in words is "two hundred trillion, two hundred ten billion, one hundred twelve million, one hundred twenty thousand, thirteen".
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