Base | Representation |
---|---|
bin | 10010101001010110… |
… | …000110101000011001 |
3 | 1220200022001211200122 |
4 | 102221112012220121 |
5 | 312000334404032 |
6 | 13110355443025 |
7 | 1306065542225 |
oct | 225126065031 |
9 | 56608054618 |
10 | 20021013017 |
11 | 8544381455 |
12 | 3a68bb6475 |
13 | 1b70b54185 |
14 | d7cdd5785 |
15 | 7c2a1c012 |
hex | 4a9586a19 |
20021013017 has 2 divisors, whose sum is σ = 20021013018. Its totient is φ = 20021013016.
The previous prime is 20021012993. The next prime is 20021013041. The reversal of 20021013017 is 71031012002.
It is a balanced prime because it is at equal distance from previous prime (20021012993) and next prime (20021013041).
It can be written as a sum of positive squares in only one way, i.e., 19580684761 + 440328256 = 139931^2 + 20984^2 .
It is a cyclic number.
It is not a de Polignac number, because 20021013017 - 222 = 20016818713 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20021012986 and 20021013004.
It is not a weakly prime, because it can be changed into another prime (20021063017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10010506508 + 10010506509.
It is an arithmetic number, because the mean of its divisors is an integer number (10010506509).
Almost surely, 220021013017 is an apocalyptic number.
It is an amenable number.
20021013017 is a deficient number, since it is larger than the sum of its proper divisors (1).
20021013017 is an equidigital number, since it uses as much as digits as its factorization.
20021013017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 84, while the sum is 17.
Adding to 20021013017 its reverse (71031012002), we get a palindrome (91052025019).
The spelling of 20021013017 in words is "twenty billion, twenty-one million, thirteen thousand, seventeen".
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