Base | Representation |
---|---|
bin | 101101100001011101000001… |
… | …100011000000101101001011 |
3 | 222020212222120211201210200001 |
4 | 231201131001203000231023 |
5 | 202220224112022400021 |
6 | 1545451355212023431 |
7 | 60112524140366503 |
oct | 5541350143005513 |
9 | 866788524653601 |
10 | 200211000200011 |
11 | 58880010139639 |
12 | 1a556296a61b77 |
13 | 8793a7c575738 |
14 | 376239aa28a03 |
15 | 1822e330e2091 |
hex | b617418c0b4b |
200211000200011 has 2 divisors, whose sum is σ = 200211000200012. Its totient is φ = 200211000200010.
The previous prime is 200211000199943. The next prime is 200211000200023. The reversal of 200211000200011 is 110002000112002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200211000200011 - 213 = 200211000191819 is a prime.
It is not a weakly prime, because it can be changed into another prime (200211000206011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100105500100005 + 100105500100006.
It is an arithmetic number, because the mean of its divisors is an integer number (100105500100006).
Almost surely, 2200211000200011 is an apocalyptic number.
200211000200011 is a deficient number, since it is larger than the sum of its proper divisors (1).
200211000200011 is an equidigital number, since it uses as much as digits as its factorization.
200211000200011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8, while the sum is 10.
Adding to 200211000200011 its reverse (110002000112002), we get a palindrome (310213000312013).
It can be divided in two parts, 2002 and 11000200011, that multiplied together give a palindrome (22022400422022).
The spelling of 200211000200011 in words is "two hundred trillion, two hundred eleven billion, two hundred thousand, eleven".
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