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200211011220151 is a prime number
BaseRepresentation
bin101101100001011101000010…
…001101000011001010110111
3222020212222121121110200110101
4231201131002031003022313
5202220224122333021101
61545451400244134531
760112524333145261
oct5541350215031267
9866788547420411
10200211011220151
1158880016386198
121a55629a697447
138793a81933729
14376239c296b31
151822e3406c401
hexb617423432b7

200211011220151 has 2 divisors, whose sum is σ = 200211011220152. Its totient is φ = 200211011220150.

The previous prime is 200211011220109. The next prime is 200211011220167. The reversal of 200211011220151 is 151022110112002.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 200211011220151 - 27 = 200211011220023 is a prime.

It is a super-2 number, since 2×2002110112201512 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200211011223151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100105505610075 + 100105505610076.

It is an arithmetic number, because the mean of its divisors is an integer number (100105505610076).

Almost surely, 2200211011220151 is an apocalyptic number.

200211011220151 is a deficient number, since it is larger than the sum of its proper divisors (1).

200211011220151 is an equidigital number, since it uses as much as digits as its factorization.

200211011220151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 80, while the sum is 19.

Adding to 200211011220151 its reverse (151022110112002), we get a palindrome (351233121332153).

The spelling of 200211011220151 in words is "two hundred trillion, two hundred eleven billion, eleven million, two hundred twenty thousand, one hundred fifty-one".