Base | Representation |
---|---|
bin | 11101001000100111000… |
… | …111011100010000111111 |
3 | 21002101210120002212221101 |
4 | 131020213013130100333 |
5 | 230300310410202033 |
6 | 4131431311313531 |
7 | 264435114616411 |
oct | 35104707342077 |
9 | 7071716085841 |
10 | 2002111022143 |
11 | 7020aa527a91 |
12 | 284032b1b8a7 |
13 | 116a4ba110bb |
14 | 6cc8cda89b1 |
15 | 3712d4c097d |
hex | 1d2271dc43f |
2002111022143 has 2 divisors, whose sum is σ = 2002111022144. Its totient is φ = 2002111022142.
The previous prime is 2002111022117. The next prime is 2002111022201. The reversal of 2002111022143 is 3412201112002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2002111022143 - 25 = 2002111022111 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2002111022143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2002111022113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001055511071 + 1001055511072.
It is an arithmetic number, because the mean of its divisors is an integer number (1001055511072).
Almost surely, 22002111022143 is an apocalyptic number.
2002111022143 is a deficient number, since it is larger than the sum of its proper divisors (1).
2002111022143 is an equidigital number, since it uses as much as digits as its factorization.
2002111022143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 2002111022143 its reverse (3412201112002), we get a palindrome (5414312134145).
The spelling of 2002111022143 in words is "two trillion, two billion, one hundred eleven million, twenty-two thousand, one hundred forty-three".
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