Base | Representation |
---|---|
bin | 11101001000100111000… |
… | …111101111100011000111 |
3 | 21002101210120020220021201 |
4 | 131020213013233203013 |
5 | 230300310420214002 |
6 | 4131431313123331 |
7 | 264435115365604 |
oct | 35104707574307 |
9 | 7071716226251 |
10 | 2002111101127 |
11 | 7020aa581365 |
12 | 284032b59547 |
13 | 116a4ba3b037 |
14 | 6cc8cdc96ab |
15 | 3712d4d9087 |
hex | 1d2271ef8c7 |
2002111101127 has 2 divisors, whose sum is σ = 2002111101128. Its totient is φ = 2002111101126.
The previous prime is 2002111101073. The next prime is 2002111101161. The reversal of 2002111101127 is 7211011112002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2002111101127 - 231 = 1999963617479 is a prime.
It is a super-3 number, since 3×20021111011273 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2002111101167) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001055550563 + 1001055550564.
It is an arithmetic number, because the mean of its divisors is an integer number (1001055550564).
Almost surely, 22002111101127 is an apocalyptic number.
2002111101127 is a deficient number, since it is larger than the sum of its proper divisors (1).
2002111101127 is an equidigital number, since it uses as much as digits as its factorization.
2002111101127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56, while the sum is 19.
Adding to 2002111101127 its reverse (7211011112002), we get a palindrome (9213122213129).
The spelling of 2002111101127 in words is "two trillion, two billion, one hundred eleven million, one hundred one thousand, one hundred twenty-seven".
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